document.write( "Question 426425: John is 6 years older than his brother. He will be twice as old as his brother in 4 years. How old is John now? \n" ); document.write( "
Algebra.Com's Answer #296646 by mananth(16946)![]() ![]() You can put this solution on YOUR website! brother's age x \n" ); document.write( "John's age x+6 \n" ); document.write( "4 years later \n" ); document.write( "brother's age x+4 \n" ); document.write( "John's age x+6+4=x +10 \n" ); document.write( "Jack is 2 times older \n" ); document.write( "x+10=2(x+4) \n" ); document.write( "x+10=2x +8 \n" ); document.write( "2x-1x=10-8 \n" ); document.write( "x=2 \n" ); document.write( "/1 \n" ); document.write( "x=2 brother's age \n" ); document.write( "x+6 =8years John's age \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |