document.write( "Question 426456: Hi i really need help with my homework. I dont know how to do this problem.
\n" ); document.write( "\"Through point (3,1) with the same slope as line 2x-3y=1\"
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Algebra.Com's Answer #296644 by mananth(16946)\"\" \"About 
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2x-3y=1
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-3y=-2x+1
\n" ); document.write( "Divide by -3
\n" ); document.write( "y=0.67x -0.33
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m =0.67
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\n" ); document.write( "The slope of a line parallel to the above line will be the same
\n" ); document.write( "The slope of the required line will be 0.67
\n" ); document.write( "m=0.67 ,point (3,1)
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "1=2+b
\n" ); document.write( "b= -1
\n" ); document.write( "m= 0.67
\n" ); document.write( "Plug value of the slope and b
\n" ); document.write( "The required equation is y =0.67x-1
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