document.write( "Question 426192: What is the general conic form equation of the hyperbola?
\n" ); document.write( "(y+1)^2/49 - (x+8)^2/196=1
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Algebra.Com's Answer #296611 by lwsshak3(11628)\"\" \"About 
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What is the general conic form equation of the hyperbola?
\n" ); document.write( "(y+1)^2/49-(x+8)^2/196=1
\n" ); document.write( "..
\n" ); document.write( "Standard forms of hyperbolas:
\n" ); document.write( "If y^2 term comes first: (y-k)^2/a^2-(x-h)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center
\n" ); document.write( "If x^2 term comes first: (x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center, as with the first form. \r
\n" ); document.write( "\n" ); document.write( "Given equation is of the first form with center at (-8,-1) and vertical transverse axis, that is, the hyperbola opens up and down.
\n" ); document.write( "a^2=49
\n" ); document.write( "a=7 (distance from center to vertices on the transverse axis.
\n" ); document.write( "Length of transverse axis=2a=14
\n" ); document.write( "b^2=196
\n" ); document.write( "b=14
\n" ); document.write( "Length of conjugate axis=2b=28
\n" ); document.write( "c^2=a^2+b^2=245
\n" ); document.write( "c=sqrt(245)=15.65..(distance from center to foci on the transverse axis)
\n" ); document.write( "Equation of asymptotes:(use y=mx+b form, with m=+-a/b=+-7/14=+-1/2, and line going thru center (-8,-1)
\n" ); document.write( "Two formulas:
\n" ); document.write( "y=x/2+3
\n" ); document.write( "y=-x/2-5
\n" ); document.write( "see the graph below:\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "y=+-(49+49(x+8)^2/196)^.5-1\r
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