document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426352>Question 426352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, \r<BR>\n" );
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document.write( "I am having serious difficulties with this problem. \r<BR>\n" );
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document.write( "[(0.125)^(-2/3)] - [3*(150)^0] + [12(2)^(-2)]\r<BR>\n" );
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document.write( "Thank you for spending the time to help me solve it. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296600 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.125 = 1/8.  Anything raised to the zeroth power is 1. And a^-b = (1/a)^b<BR>\n" );
document.write( "Therefore, this expression simplifies to<BR>\n" );
document.write( "(1/8)^(-2/3) - 3*1 + 12(2)^(-2) -> 8^(2/3) - 3 + 12/(2)^2 -> 4 - 3 + 3 = 4<BR>\n" );
document.write( "Answer: 4 </SPAN>\n" );
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