document.write( "Question 426246: 1) probability of 59, with Mean=60, and Standard deviation=7?
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document.write( " My answer: X=59
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document.write( " z=(59-60)/7
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document.write( " z= -0.143
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document.write( " p= 0.444
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document.write( " p=0.444, .04<.05, Decision to REJECT, Possible Error Type I
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document.write( " APA Statement: The hypothesis was supported X=45 s, z=0.143, p= 0.44
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document.write( " This is a one tailed hypotheisis.
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document.write( " Is my answer correct?\r
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document.write( "2)score at z = –1.96
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document.write( "I am not sure how to figure it out \n" );
document.write( "
Algebra.Com's Answer #296559 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1) probability of 59, with Mean=60, and Standard deviation=7? \n" ); document.write( "My answer: X=59 \n" ); document.write( "z=(59-60)/7 \n" ); document.write( "z= -0.143 \n" ); document.write( "p= 0.444 \n" ); document.write( "p=0.444, .04<.05, Decision to REJECT, Possible Error Type I \n" ); document.write( "APA Statement: The hypothesis was supported X=45 s, z=0.143, p= 0.44 \n" ); document.write( "This is a one tailed hypotheisis. \n" ); document.write( "Is my answer correct? \n" ); document.write( "------- \n" ); document.write( "I don't think you are right. \n" ); document.write( "z(59) = -0.143 \n" ); document.write( "Assuming you have a left-tail test the p-value \n" ); document.write( "is P(z < -0.143) = 0.443 \n" ); document.write( "That is not less than 5% so the decision is to \n" ); document.write( "not reject Ho. \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( "2)score at z = –1.96 \n" ); document.write( "I am not sure how to figure it out \n" ); document.write( " \n" ); document.write( " |