document.write( "Question 426103: The length of a rectangle is 8 cm more than two times the width. If the perimeter of the rectangle is 40 cm, what are the dimensions?
\n" ); document.write( "A) width = 4 cm, length = 16 cm
\n" ); document.write( "B) width = 8 cm, length = 24 cm
\n" ); document.write( "C) width = 4 cm, length = 32 cm
\n" ); document.write( "D) width = 8 cm, length = 32 cm
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Algebra.Com's Answer #296501 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "The length of a rectangle is 8 cm more than two times the width
\n" ); document.write( "Let x and (2x+8cm) represent the widthe and length respectively
\n" ); document.write( "Question states***
\n" ); document.write( " 2(2x+8) + 2x = 40cm
\n" ); document.write( "Solving for x
\n" ); document.write( " 6x = 24
\n" ); document.write( " x = 4cm. the width, the length is 16cm. (2*4cm + 8cm)\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 2*16cm + 2*4cm = 40cm
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