document.write( "Question 5740: I'm having difficulty figuring out determinants for matricies that exceed the normal 3x3 format. The exact matrix is as follows:
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document.write( "1 2 0 0
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document.write( "3 -1 4 5
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document.write( "-2 4 1 6
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document.write( "2 -1 -2 -3\r
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document.write( "Our book explains that if two rows or columns of a square matrix A are identical, then the absolute value of A = 0 ... but none of these rows or columns are identical. I have tried the D=a11C11+a21C21+a31C31 and adding in the fourth a41C41, but my answer wasn't correct (understandably so). \r
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document.write( "Any piece of information is helpful. Thank you,
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document.write( "Abby \n" );
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Algebra.Com's Answer #2965 by khwang(438)![]() ![]() ![]() You can put this solution on YOUR website! Since the 1st row containing twozeros, \n" ); document.write( " expanding it along the 1st row, we have \n" ); document.write( " D = a11C11 - a12C12 = 1*(-20) + (-2)*61 = -142\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Kenny\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |