document.write( "Question 426053: Find the length and width of a rectangle that has the given perimeter and a maximum area.
\n" ); document.write( "Perimeter: 48 meters
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Algebra.Com's Answer #296486 by Gogonati(855)\"\" \"About 
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Solution:Denote the length of rectangle x m, since the perimeter is 48m then the width of rectangle is (24-x)m. We know that the area of rectangle is:\r
\n" ); document.write( "\n" ); document.write( " \"A=x%2A%2824-x%29\"\r
\n" ); document.write( "\n" ); document.write( " \"A=-x%5E2%2B24x\" This function introduce a downward parabola.\r
\n" ); document.write( "\n" ); document.write( "We find the vertex of this parabola: \"x=%28-24%29%2F%28-2%29=12\"\r
\n" ); document.write( "\n" ); document.write( "Since the length is 12m the width will be: 24-12=12m\r
\n" ); document.write( "\n" ); document.write( "We conclude that this rectangle has the maximum area when its shape is square of side 12m.\r
\n" ); document.write( "\n" ); document.write( " We find the value of area for x=12m : \"A%2812%29=-%2812%29%5E2%2B24%2A12\"\r
\n" ); document.write( "\n" ); document.write( " \"+A%2812%29=144+m%5E2\".\r
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