document.write( "Question 426006: a man left home driving at 40 miles per hour.when his car broke down, he walked home at a rate of 5 miles per hour;the entire trip (driving and walking) took him 2 1/4 hours. how far from his house did his car break down. \n" ); document.write( "
Algebra.Com's Answer #296451 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are two ways to go about this. The direct way goes right at the quantity we want to determine, but requires more and more difficult calculations. We'll look at this way first.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We know that distance equals rate times time. This implies that time is equal to distance divided by rate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the outbound, or driving, part of the trip, we can describe the situation thus:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And the return, or walking, part of the trip, the situation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Manipulating the second equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now that we have two expressions that are both equal to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now all you have to do is cross-multiply, collect like terms, and solve for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The indirect method is a little simpler on the arithmetic:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use distance equals rate times time to create two equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |