document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425947>Question 425947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My problem question is find the linear function with the following properties f(2)=-10 slope equals -4/3. I have first step -4/3a=-4/3f(2)=-10 second step -10=f(2) third step -10=4/3(2)+b fourth step -10=-8/3+b. Now I'm stuck how to get the answer.  Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296419 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have essentially solved the problem.<BR>\n" );
document.write( "Just solve for b:<BR>\n" );
document.write( "Your 4th step has -10 = -8/3 + b -> b = -10 + 8/3 = -30/3 + 8/3 = -22/3<BR>\n" );
document.write( "So the function is <BR>\n" );
document.write( "f(x) = (-4/3)x - 22/3<BR>\n" );
document.write( "The graph looks like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%28-4%2F3%29x+-+22%2F3%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%28-4%2F3%29x+-+22%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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