document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425938>Question 425938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B are running on a track having 8 laps to a mile. If they run in opposite directions, they meet every 20s. If they run in the same direction, it requires 3mins for A to overtake B. Find the rate of each in feet per second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296418 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A and B are running on a track having 8 laps to a mile.<BR>\n" );
document.write( " If they run in opposite directions, they meet every 20s.<BR>\n" );
document.write( " If they run in the same direction, it requires 3mins for A to overtake B.<BR>\n" );
document.write( " Find the rate of each in feet per second.<BR>\n" );
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document.write( "Let a = running speed of A, ft/sec<BR>\n" );
document.write( "let b = running speed of B<BR>\n" );
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document.write( "Change 3 min to 180 sec<BR>\n" );
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document.write( "Size of circular track = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" > * 5280 = 660 ft<BR>\n" );
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document.write( "Write a dist equation for each direction; dist = time * speed<BR>\n" );
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document.write( "20a + 20b = 660, opposite direction<BR>\n" );
document.write( "180a - 180b = 660, same direction<BR>\n" );
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document.write( "multiply 1st equation by 9, add to 2nd equation<BR>\n" );
document.write( "180a + 180b = 5940<BR>\n" );
document.write( "180a - 180b = 660<BR>\n" );
document.write( "-----------------------adding eliminates b, find a<BR>\n" );
document.write( "360a = 6600<BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6600%2F360 ALIGN=MIDDLE  ALT=\"6600%2F360\"   DISABLED_style= \"max-width:90%; height:auto;\" > ft/sec is A's running speed<BR>\n" );
document.write( "a = 18.333 or 18<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > ft/sec<BR>\n" );
document.write( "then<BR>\n" );
document.write( "20*18.333 + 20b = 660<BR>\n" );
document.write( "366.66 + 20b = 660<BR>\n" );
document.write( "20b = 660 - 366.66<BR>\n" );
document.write( "20b = 293.333<BR>\n" );
document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=293.333%2F20 ALIGN=MIDDLE  ALT=\"293.333%2F20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b = 14.67 ft/sec is B's running speed<BR>\n" );
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document.write( "We can check this by finding the total distance they ran in 20 sec<BR>\n" );
document.write( "20*18.333 = 366.66 ft<BR>\n" );
document.write( "20*14.667 = 293.34 ft<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "total dist: 660 ft\r<BR>\n" );
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document.write( " </SPAN>\n" );
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