document.write( "Question 425935: hi am stuck on the cotangent formula for triangles
\n" ); document.write( "how do we get from number 1 to number 2 \r
\n" ); document.write( "\n" ); document.write( "1. m{cot α-cotθ} = n{cot β + cot θ}\r
\n" ); document.write( "\n" ); document.write( "2. (m+n) cot θ = m cot α - n cot β
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Algebra.Com's Answer #296414 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this looks like it's straight algebra manipulation.\r
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\n" ); document.write( "\n" ); document.write( "let a = cot(alpha)
\n" ); document.write( "let b = cot(beta)
\n" ); document.write( "let t = cot(theta)\r
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\n" ); document.write( "\n" ); document.write( "t is equal to the lower case T, no to be confused with + which is the plus sign.\r
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\n" ); document.write( "\n" ); document.write( "you start with m*(a-t) = n*(b+t)\r
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\n" ); document.write( "\n" ); document.write( "multiply out each factor to get:\r
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\n" ); document.write( "\n" ); document.write( "m*a - m*t = n*b + n*t\r
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\n" ); document.write( "\n" ); document.write( "add m*t to both sides of the equation and subtract n*b from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "m*a - n*b = m*t + n*t\r
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\n" ); document.write( "\n" ); document.write( "factor to get:\r
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\n" ); document.write( "\n" ); document.write( "m*a - n*b = (m+n)*t\r
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\n" ); document.write( "\n" ); document.write( "commute to get:\r
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\n" ); document.write( "\n" ); document.write( "(m+n)*t = m*a - n*b\r
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\n" ); document.write( "\n" ); document.write( "substitute for t,a,b to get:\r
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\n" ); document.write( "\n" ); document.write( "(m+n) * cot (theta) = m*cot(alpha) - n*cot(beta)\r
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