document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425907>Question 425907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	A train left Town A at 8:50 a.m., it passed Town B at 9:30 a.m. and arrived at Town C at 10:30 a.m. The distance between Town A and Town B is 100 km. Between Town B and Town C, the train travelled at 110 km/h. What was the average speed of the train for the whole journey? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296407 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A to B is 100 km<BR>\n" );
document.write( "B to c speed 110 km/h traveled for 1 hour so distance = 110 km.\r<BR>\n" );
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document.write( "Total distance = 210 km<BR>\n" );
document.write( "Total time = 10:30 - 8:50 = 1 h 40 minutes = 1  2/3 hours===> 5/3 hours<BR>\n" );
document.write( "Rate = distance / time <BR>\n" );
document.write( "Rate = 210/(5/3)<BR>\n" );
document.write( "Rate = 210*3/5<BR>\n" );
document.write( "Rate = 42*3<BR>\n" );
document.write( "Rate = 126 km/h  ====> average speed of the journey </SPAN>\n" );
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