document.write( "Question 425905: How to find the vertx, value of p, axis of symmetry, focus, and directrix of each porabola, and then graph.
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document.write( "y= 1/32(x+)^2
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document.write( "hOW TO write the eqauation in standrard for for each porabola
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document.write( "a. vertex (0,0), focus(0,1)
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document.write( "b. vertex(0,0), focus (-8,0) \n" );
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Algebra.Com's Answer #296405 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How to find the vertx, value of p, axis of symmetry, focus, and directrix of each parabola, and then graph. \n" ); document.write( "y= (1/32)x^2 \n" ); document.write( "hOW TO write the equation in standard for for each porabola \n" ); document.write( "a. vertex (0,0), focus(0,1) \n" ); document.write( "b. vertex(0,0), focus (-8,0)\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "y=1/32(x^2 \n" ); document.write( "This of the form, (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex. Since you don't see h or k in the equation, the vertex must be at the origin, (0,0). \n" ); document.write( "rewriting given equation, \n" ); document.write( "x^2=32y \n" ); document.write( "This is a parabola that opens upwards with its vertex at the (0,0), and axis of symmetry,x=0 or the y-axis. \n" ); document.write( "4p=32 \n" ); document.write( "p=8 \n" ); document.write( "The focus on the axis of symmetry is 8 units above the center at (0,8). \n" ); document.write( "The directrix is a line, y=-8 \n" ); document.write( "See the graph of this parabola below: \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "a. vertex (0,0), focus(0,1) \n" ); document.write( "From the focal point (0,1), it can be seen that the axis of symmetry is the y-axis like the previous parabola and it opens upwards with p=1 and its directrix at y=-1 \n" ); document.write( "Equation: x^2=4y \n" ); document.write( "See the graph below:(Note that the higher the coefficient of x^2, the steeper the curve, that is, a higher slope) \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "b. vertex(0,0), focus (-8,0) \n" ); document.write( "Again, gleaning information from the focal point, it can be seen that the axis of symmetry is x=0 or the x-axis and it opens sideways to the left with p=8 and its directrix at x=8. \n" ); document.write( "Equation: \n" ); document.write( "y^2=-32x \n" ); document.write( "See the graph below: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |