document.write( "Question 425905: How to find the vertx, value of p, axis of symmetry, focus, and directrix of each porabola, and then graph.
\n" ); document.write( "y= 1/32(x+)^2
\n" ); document.write( "hOW TO write the eqauation in standrard for for each porabola
\n" ); document.write( "a. vertex (0,0), focus(0,1)
\n" ); document.write( "b. vertex(0,0), focus (-8,0)
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Algebra.Com's Answer #296405 by lwsshak3(11628)\"\" \"About 
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How to find the vertx, value of p, axis of symmetry, focus, and directrix of each parabola, and then graph.
\n" ); document.write( "y= (1/32)x^2
\n" ); document.write( "hOW TO write the equation in standard for for each porabola
\n" ); document.write( "a. vertex (0,0), focus(0,1)
\n" ); document.write( "b. vertex(0,0), focus (-8,0)\r
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\n" ); document.write( "\n" ); document.write( "y=1/32(x^2
\n" ); document.write( "This of the form, (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex. Since you don't see h or k in the equation, the vertex must be at the origin, (0,0).
\n" ); document.write( "rewriting given equation,
\n" ); document.write( "x^2=32y
\n" ); document.write( "This is a parabola that opens upwards with its vertex at the (0,0), and axis of symmetry,x=0 or the y-axis.
\n" ); document.write( "4p=32
\n" ); document.write( "p=8
\n" ); document.write( "The focus on the axis of symmetry is 8 units above the center at (0,8).
\n" ); document.write( "The directrix is a line, y=-8
\n" ); document.write( "See the graph of this parabola below:
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\n" ); document.write( "\"+graph%28+200%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F32%29x%5E2%2C-8%29+\"\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "a. vertex (0,0), focus(0,1)
\n" ); document.write( "From the focal point (0,1), it can be seen that the axis of symmetry is the y-axis like the previous parabola and it opens upwards with p=1 and its directrix at y=-1
\n" ); document.write( "Equation: x^2=4y
\n" ); document.write( "See the graph below:(Note that the higher the coefficient of x^2, the steeper the curve, that is, a higher slope)
\n" ); document.write( "..
\n" ); document.write( "\"+graph%28+200%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E2%2F4%2C-1%29+\"
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\n" ); document.write( "\n" ); document.write( "b. vertex(0,0), focus (-8,0)
\n" ); document.write( "Again, gleaning information from the focal point, it can be seen that the axis of symmetry is x=0 or the x-axis and it opens sideways to the left with p=8 and its directrix at x=8.
\n" ); document.write( "Equation:
\n" ); document.write( "y^2=-32x
\n" ); document.write( "See the graph below:
\n" ); document.write( "\"+graph%28+200%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C%28-32x%29%5E.5%2C-%28-32x%29%5E.5%29+\"
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