document.write( "Question 44769: another question, sorry again =]
\n" ); document.write( "How much of a 20% acid solution should be mixed with 80 mL of 5% acid solution to obtain a 12% acid solution?\r
\n" ); document.write( "\n" ); document.write( "well, i tried it, but no luck...
\n" ); document.write( "0.20(x mL) + 0.05(80 mL) = 0.12(80 + x)
\n" ); document.write( "but when i solve it, the answer doesn't come out reasonable..maybe im solving it wrong, i don't know, but please help =]
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Algebra.Com's Answer #29639 by shalu.srk(1)\"\" \"About 
You can put this solution on YOUR website!
\"0.20x%2B0.05%2880+mL%29=0.12%2880%2Bx%29\"
\n" ); document.write( "distribute all the things that can be distributed =]
\n" ); document.write( "\"0.20x%2B4=9.6%2B0.12x\"
\n" ); document.write( "\"0.20x=5.6%2B0.12x\"
\n" ); document.write( "\"0.08x=5.6\"
\n" ); document.write( "\"5.6%2F0.08=x=70+mL\"
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