document.write( "Question 425709: Prove the identity:\r
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Algebra.Com's Answer #296336 by AnlytcPhil(1806)\"\" \"About 
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Prove the identity:\r
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document.write( "We will work with just the left side:\r\n" );
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document.write( "Use the quotient identity \"Cot%28theta%29=Cos%28theta%29%2FSin%28theta%29\"\r\n" );
document.write( "to rewrite the first term:\r\n" );
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document.write( "\"-%28Cosx%29%2F%28Sinx%29+%2B+Sinx%2F%281-Cosx%29\"\r\n" );
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document.write( "Multiply the second fraction by \"red%28%28%281%2BCosx%29%29%2F%28%281%2BCosx%29%29%29\"\r\n" );
document.write( "which just equals 1:\r\n" );
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document.write( "Multiply the fractions:\r\n" );
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document.write( "\"-%28Cosx%29%2F%28Sinx%29+%2B+%28Sinx%281%2BCosx%29%29%2F%281-Cos%5E2x%29\"\r\n" );
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document.write( "Use the Pythagorean identity \"Sin%5E2theta%2BCos%5E2theta=1\" written as \"1-Cos%5E2theta=Sin%5E2theta\"\r\n" );
document.write( "to replace the second denominator:\r\n" );
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document.write( "\"-%28Cosx%29%2F%28Sinx%29+%2B+%28Sinx%281%2BCosx%29%29%2F%28Sin%5E2x%29\"\r\n" );
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document.write( "Simplify the second term on the bottom:\r\n" );
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document.write( "\"-%28Cosx%29%2F%28Sinx%29+%2B+%28cross%28Sinx%29%281%2BCosx%29%29%2F%28Sin%5Ecross%282%29x%29\"\r\n" );
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document.write( "\"-%28Cosx%29%2F%28Sinx%29+%2B+%281%2BCosx%29%2F%28Sinx%29\"\r\n" );
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document.write( "The denominators are the same so we can combine the\r\n" );
document.write( "two fractions by combining the numerators over the\r\n" );
document.write( "common denominator:\r\n" );
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document.write( "\"%28-Cosx%2B1%2BCosx%29%2F%28Sinx%29\"\r\n" );
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document.write( "Simplify the numerator:\r\n" );
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document.write( "\"%28cross%28-Cosx%29%2B1%2Bcross%28Cosx%29%29%2F%28Sinx%29\"\r\n" );
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document.write( "\"1%2F%28Sinx%29\"\r\n" );
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document.write( "Use the reciprocal identity \"Csc%28theta%29=1%2FSin%28theta%29\"\r\n" );
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document.write( "\"Csc%28x%29\"\r\n" );
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document.write( "Edwin
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