document.write( "Question 425642: This ellipse is centered at the origin and has a horizontal axis of length 16 and a vertical axis of length 8. What is its equation?\r
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Algebra.Com's Answer #296316 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! This ellipse is centered at the origin and has a horizontal axis of length 16 and a vertical axis of length 8. What is its equation?\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "Standard form for this ellipse: \n" ); document.write( "(x-h)^2/a^2+(y-k)^2/b^2=1,(a>b) with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "In this case since the center is at (0,0) the equation becomes: \n" ); document.write( "x^2/a^2+y^2/b^2=1 (a>b) All we need to do is find a^2 & b^2 to get the equation. \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "2a=major axis as given =16 \n" ); document.write( "a=8 \n" ); document.write( "a^2=64 \n" ); document.write( "2b=minor axis as given = 8 \n" ); document.write( "b=4 \n" ); document.write( "b^2=16\r \n" ); document.write( "\n" ); document.write( "Equation of the ellipse: \n" ); document.write( "x^2/64+y^2/16=1 \n" ); document.write( "The graph below shows what this ellipse looks like.\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "y=+-(16(1-x^2/64))^.5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |