document.write( "Question 44768: A jar full of nickels and dimes contains 180 coins . If the total amount of money contained in the jar is $13.000, how many nickels are in the jar?\r
\n" ); document.write( "\n" ); document.write( "I set up the equation,
\n" ); document.write( "$0.05x + 0.10y = $13.00
\n" ); document.write( "and x + y = 180
\n" ); document.write( "x=nickels and y=dimes\r
\n" ); document.write( "\n" ); document.write( "i really don't remember how to solve it now, since it has two variables...please if someone could help me, i would really appreciate it [please by today?] thanks
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Algebra.Com's Answer #29629 by adamchapman(301)\"\" \"About 
You can put this solution on YOUR website!
Just get your equation \"x%2By=180\", rearrang to give y in terms of x:
\n" ); document.write( "\"y=180-x\"
\n" ); document.write( "Now substituite this into the other equation you started with:
\n" ); document.write( "\"%240.05x%2B%240.1y=%2413\"
\n" ); document.write( "\"%240.05x%2B%240.1%28180-x%29=%2413\"
\n" ); document.write( "\"0.05x%2B18-0.1x=13\"
\n" ); document.write( "\"-0.05x%2B18=13\"
\n" ); document.write( "\"0.05x=5\"
\n" ); document.write( "\"0.01x=1\"
\n" ); document.write( "\"x=1%2F0.01\"
\n" ); document.write( "\"x=100\"
\n" ); document.write( "Now substitute this value of x into your equation for y:
\n" ); document.write( "\"y=180-x\"
\n" ); document.write( "\"y=180-100=80\"
\n" ); document.write( "So the pot contains 100 nickels and 80 dimes.\r
\n" ); document.write( "\n" ); document.write( "I hope this helps.
\n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
\n" ); document.write( "Adam\r
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