document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425438>Question 425438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times the square of a positive number when added to the 7 times of the number result is 26  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296245 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "3x^2 + 7x = 26\r<BR>\n" );
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document.write( "=> 3x^2 +7x -26 =0\r<BR>\n" );
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document.write( "=>  3x^2 -6x + 13x -26 =0\r<BR>\n" );
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document.write( "=> 3x(x -2) +13(x -2) = 0\r<BR>\n" );
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document.write( "=> (3x+13)(x-2)=0\r<BR>\n" );
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document.write( "=> x = 2, -13/3\r<BR>\n" );
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document.write( "so number is 2.\r<BR>\n" );
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