document.write( "Question 421618: Show that log(8- base) 1000 = log (2- base) 10 algebraically. \n" ); document.write( "
Algebra.Com's Answer #296236 by lwsshak3(11628)\"\" \"About 
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Show that log(8- base) 1000 = log (2- base) 10 algebraically.\r
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\n" ); document.write( "\n" ); document.write( "log8(1000)=x
\n" ); document.write( "log2(10)=x
\n" ); document.write( "convert both equations to exponential form. The base raised to the logarithm of the number is equal to the number.
\n" ); document.write( "8^x=1000
\n" ); document.write( "(2^3)^x=1000
\n" ); document.write( "2^3x=1000
\n" ); document.write( "..
\n" ); document.write( "2^x=10
\n" ); document.write( "cube both sides
\n" ); document.write( "(2^x)^3=10^3
\n" ); document.write( "2^3x=1000\r
\n" ); document.write( "\n" ); document.write( "ans: equations therefore are algebraically equal to each other.\r
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