document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425281>Question 425281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the center and radius of a circle that has a diameter with endpoints (-4,-19) and (12, 11. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296229 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The center is the midpoint of the endpoints, so the center is at (4, -4) (obtain this by taking the average of the x-coordinates, average of the y-coordinates). The radius of the circle is the distance from (4, -4) to, say, (12, 11). By the distance formula, this is equal to\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28%2812-4%29%5E2+%2B+%2811-%28-4%29%29%5E2%29+=+sqrt%288%5E2+%2B+15%5E2%29+=+17 ALIGN=MIDDLE  ALT=\"r+=+sqrt%28%2812-4%29%5E2+%2B+%2811-%28-4%29%29%5E2%29+=+sqrt%288%5E2+%2B+15%5E2%29+=+17\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the radius is 17. </SPAN>\n" );
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