document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44757>Question 44757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I need help factoring 2x^2-2x-40   \r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29621 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2 - 2x - 40 find the sum of the factors of (2 * -40) to get (-2): 8 and -10<BR>\n" );
document.write( "2x^2 + 8x - 10x - 40<BR>\n" );
document.write( "(2x^2 + 8x) + (-10x - 40)<BR>\n" );
document.write( "2x(x + 4) - 10(x + 4)<BR>\n" );
document.write( "(2x - 10)(x + 4) </SPAN>\n" );
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