document.write( "Question 425353: A 280 ML solution is 20% salt. How much water should be added to make the solution 14% salt?\r
\n" ); document.write( "\n" ); document.write( "This is an extra credit question but I really want the bonus points. Here's what I've already tried:
\n" ); document.write( "20% of 280 is 56 ML. So then I found 14% of 280 and got 39.2 ML, so would my answer be 240.8 ML (I subtracted 39.2 from 280) of water would be needed to make the solution 14% salt, or am I completely off? Thank you sooo much! : ) \n" ); document.write( "

Algebra.Com's Answer #296209 by Gersid(33) $\"\"$ $\"About$

You can put this solution on YOUR website!
Well, not quite!
\n" ); document.write( "Think about how much salt there is in the initial solution.
\n" ); document.write( "280(0.2) = 56 ml of salt.
\n" ); document.write( "You are not adding any salt to make the new solution, just water, so the amount of salt will be unchanged, only its concentration changes. So...
\n" ); document.write( "280(0.2) = (x+280)(0.14) x is the amount of water you will add.
\n" ); document.write( "56 = 0.14x + 39.2 Subtract 39.2 from both sides.
\n" ); document.write( "16.8 = 0.14x Divide both sides by 0.14
\n" ); document.write( "x = 120
\n" ); document.write( "So you would need to add 120 ml. of water to the 280 ml. of 20% salt solution to get 400 ml. of 14% salt solution.
\n" ); document.write( "Check:
\n" ); document.write( "280(0.2) = (280+120)(0.14)
\n" ); document.write( "56 = 400(0.14)
\n" ); document.write( "56 = 56 \n" ); document.write( "

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