document.write( "Question 425353: A 280 ML solution is 20% salt. How much water should be added to make the solution 14% salt?\r
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document.write( "This is an extra credit question but I really want the bonus points. Here's what I've already tried:
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document.write( "20% of 280 is 56 ML. So then I found 14% of 280 and got 39.2 ML, so would my answer be 240.8 ML (I subtracted 39.2 from 280) of water would be needed to make the solution 14% salt, or am I completely off? Thank you sooo much! : ) \n" );
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Algebra.Com's Answer #296207 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A 280 ML solution is 20% salt. \n" ); document.write( " How much water should be added to make the solution 14% salt? \n" ); document.write( ": \n" ); document.write( "Do it like this \n" ); document.write( "Let w = amt of water required to accomplish this \n" ); document.write( ": \n" ); document.write( "Amt of salt does not change, only the percent salt changes \n" ); document.write( ".20(280) = .14(w+280) \n" ); document.write( "56 = .14w + 39.2 \n" ); document.write( "56 - 39.2 = .14w \n" ); document.write( "16.8 = .14w \n" ); document.write( "w = \n" ); document.write( "w = 120 ml of water required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( ".20(280) = .14(120+280) \n" ); document.write( ".20(280) = .14(400) \n" ); document.write( "56 = 56 \n" ); document.write( " |