document.write( "Question 425353: A 280 ML solution is 20% salt. How much water should be added to make the solution 14% salt?\r
\n" ); document.write( "\n" ); document.write( "This is an extra credit question but I really want the bonus points. Here's what I've already tried:
\n" ); document.write( "20% of 280 is 56 ML. So then I found 14% of 280 and got 39.2 ML, so would my answer be 240.8 ML (I subtracted 39.2 from 280) of water would be needed to make the solution 14% salt, or am I completely off? Thank you sooo much! : )
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Algebra.Com's Answer #296207 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A 280 ML solution is 20% salt.
\n" ); document.write( " How much water should be added to make the solution 14% salt?
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\n" ); document.write( "Do it like this
\n" ); document.write( "Let w = amt of water required to accomplish this
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\n" ); document.write( "Amt of salt does not change, only the percent salt changes
\n" ); document.write( ".20(280) = .14(w+280)
\n" ); document.write( "56 = .14w + 39.2
\n" ); document.write( "56 - 39.2 = .14w
\n" ); document.write( "16.8 = .14w
\n" ); document.write( "w = \"16.8%2F.14\"
\n" ); document.write( "w = 120 ml of water required
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\n" ); document.write( "Check this
\n" ); document.write( ".20(280) = .14(120+280)
\n" ); document.write( ".20(280) = .14(400)
\n" ); document.write( "56 = 56
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