document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425183>Question 425183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2. Write each of the following quadratic functions in the form y=ax^2 + bx + c. \r<BR>\n" );
document.write( "\n" );
document.write( "a) y= 2x^2 - 7\r<BR>\n" );
document.write( "\n" );
document.write( "b) f(x) = 4(x-1)(x+3) <BR>\n" );
document.write( "=4x^2 + 2x - 3(Is this CORRECT???)\r<BR>\n" );
document.write( "\n" );
document.write( "c) 2(y-4)+7x=-3(x+1)^2-5\r<BR>\n" );
document.write( "\n" );
document.write( "Kinda unsure of this whole question. Thanks! Help is appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296160 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a) is already in the correct form.<BR>\n" );
document.write( "For (b), multiply the two product terms using FOIL, then multiply through by 4:<BR>\n" );
document.write( "f(x) = 4(x^2 + 2x - 3) = 4x^2 + 8x - 12 <BR>\n" );
document.write( "[Your answer would have been correct, except you didn't multiply all the terms by '4']<BR>\n" );
document.write( "For (c), carry out the multiplication and collect like terms:<BR>\n" );
document.write( "2y - 8 + 7x = -3(x^2 + 2x + 1) - 5<BR>\n" );
document.write( "2y - 8 + 7x = -3x^2 - 6x - 3 - 5<BR>\n" );
document.write( "2y = -3x^2 - 13x - 8 + 8<BR>\n" );
document.write( "So we have y = (-3/2)x^2 - (13/2)x <BR>\n" );
document.write( "Let's check our answer to (c) with a simple example.  Let x = 1<BR>\n" );
document.write( "Original equation gives 2(y-4) + 7 = -3(2)^2 - 5 -> 2y - 8 + 7 = -12 - 5 -> y = -8<BR>\n" );
document.write( "Solved equation gives y = (-3/2)(1)^2 - (13/2)(1) - > y = -16/2 = -8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );