document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424507>Question 424507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve the following:\r<BR>\n" );
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document.write( "Establish the identity\r<BR>\n" );
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document.write( "2secX = cosX/(1+sinX) + (1+sinX)/cosX </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296157 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How to solve the following:<BR>\n" );
document.write( "Establish the identity<BR>\n" );
document.write( "2secX = cosX/(1+sinX) + (1+sinX)/cosX<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Starting from the right side,<BR>\n" );
document.write( "cosX/(1+sinX)+(1+sinX)/cosX<BR>\n" );
document.write( "add the two fractions using LCD, cosx(1+sinx)<BR>\n" );
document.write( "=cos^2x+(1+sinx)^2/cosx(1+sinx)<BR>\n" );
document.write( "=cos^2x+1+2sinx+sin^2x/cosx(1+sinx)<BR>\n" );
document.write( "cos^2x+sin^2x=1<BR>\n" );
document.write( "=2+2sinx/cosx(1+sinx)<BR>\n" );
document.write( "=2(1+sinx)/cosx(1+sinx)<BR>\n" );
document.write( "=2/cosx<BR>\n" );
document.write( "=2secx<BR>\n" );
document.write( "Identity established: right side=left side </SPAN>\n" );
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