document.write( "Question 425163: how do i do this?
\n" ); document.write( "m∠ROS = 20 deg 15' 40\", m∠SOT = 10 ° 12' 30\"
\n" ); document.write( "m∠ROT =
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Algebra.Com's Answer #296155 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Degrees may be further divided into minutes and seconds, but that division is not as universal as it used to be.\r
\n" ); document.write( "\n" ); document.write( "Each degree is divided into 60 equal parts called minutes. \r
\n" ); document.write( "\n" ); document.write( "Each minute is further divided into 60 equal parts called seconds.\r
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\n" ); document.write( "\n" ); document.write( "m∠ROS = 20° 15' 40\", m∠SOT = 10 ° 12' 30\"\r
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\n" ); document.write( "\n" ); document.write( "m∠ROT=180° - (m∠ROS + m∠SOT)\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=180° - (20° 15' 40\" + 10 ° 12' 30\")\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=180° - (30° 27' 70\" )...............70\"=1' 10\"\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=180° - (30° 28' 10\" )..\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=180° - (30° 28' 10\" ).......take 1° from 180° and convert to minutes, then take one minute and convert to seconds\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=179° 59' 60\" - 30° 28' 10\" ..now subtract degrees from degrees, minutes from minutes, and seconds from seconds\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=(179°-30°) (59'-28' ) (60\" -10\")\r
\n" ); document.write( "\n" ); document.write( "m∠ROT=149° 31' 50\" \r
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