document.write( "Question 425049: For a trip a woman packed 8 tops, 3 pair of pants, and 2 pairs of shoes. How many different outfits can she wear? \n" ); document.write( "
Algebra.Com's Answer #296120 by Gogonati(855)![]() ![]() You can put this solution on YOUR website! Solution:Using the fundamental principle of counting we have: 8X3X2=48.\r \n" ); document.write( "\n" ); document.write( "Answer:She can wear 48 different outfits. \n" ); document.write( " |