document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=425062>Question 425062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> assume you invest 2000$ at 3.5% compounded continuously, construct an equation that describes the value of your invesment at year t </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296115 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution: Denote P=2000 the initial amount invested, r=3.5%=0.035 the interest rate and t the amount of time the investment is held. The compounded continuously A(t) can be given from the equation: ( A(t) is the value of investment after t- years)\r<BR>\n" );
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document.write( "    <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%28t%29=P%2Ae%5Er%2At ALIGN=MIDDLE  ALT=\"A%28t%29=P%2Ae%5Er%2At\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "    <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%28t%29=2000%2Ae%5E%280.035t%29 ALIGN=MIDDLE  ALT=\"A%28t%29=2000%2Ae%5E%280.035t%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where e=2.718281... </SPAN>\n" );
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