document.write( "Question 424968: prove that 1+1 is equal to 2 \n" ); document.write( "
Algebra.Com's Answer #296100 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A few simple definitions in Peano terms. 1 is the successor of 0, or S0. 2 is the successor of 1, or so on\r \n" ); document.write( "\n" ); document.write( "Any equation is equal to itself, so we can start with S0 + S0 = S0 + S0 (1 + 1 = 1 + 1)\r \n" ); document.write( "\n" ); document.write( "Any expression of the form A + SB is equivalent to SA + B, so S0 + S0 is equivalent to SS0 + 0. Thusly we can prove that ( \n" ); document.write( "\n" ); document.write( "Since the expressions X + 0 and X are of equal value (by the Peano definition of addition,) SS0 + 0 can be reduced to SS0. Thus, we have proved that 1 + 1 = 2 according to Peano's axioms. (I think... hopefully I haven't skipped over anything or taken an illegal shortcut. It's been a while since I've worked with Peano.)\r \n" ); document.write( "\n" ); document.write( "Algebraically, we can approach the problem somewhat simpler:\r \n" ); document.write( "\n" ); document.write( "Take \n" ); document.write( "\n" ); document.write( "subtract \n" ); document.write( "\n" ); document.write( "Simplifying both sides, you can get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |