document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424888>Question 424888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the values of the constant A in the equation 3(x+4)(x+A)=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296080 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:The equation has two roots: X1=-4 and X2=-A, where A>0.<BR>\n" );
document.write( "         Our equation can be written:3x^2+12x+3Ax+12A=0 => 3x^2+(3A+12)x+12A=0\r<BR>\n" );
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document.write( " Using Vi eta's Formula X1+X2=-b/2a and X1*X2=c/a where a=3, b=3A+12 and c=12A :\r<BR>\n" );
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document.write( "   -4-A=-(3A+12)/6 => 4+A=(1/2)A+2 =>A-A/2=-2 => A/2=-2 => A=-4\r<BR>\n" );
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document.write( " -4X2=12A/3 =>-4X2=4A =>X2=-A => X2=-(-4)=4.\r<BR>\n" );
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document.write( "Answer: The value of A=-4. </SPAN>\n" );
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