document.write( "Question 424948: i really need help solving this problem ive aldready done a few steps but not sure if im doing them right.\r
\n" ); document.write( "\n" ); document.write( "A 10% acid solution is to be mixed with a 50% solution to get 200 liters of a 20% solution. How many liters of each solution should be used ?
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Algebra.Com's Answer #296079 by mananth(16949)\"\" \"About 
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percent ----------------quantity
\n" ); document.write( "Acid solution A 10 ----------------x liters
\n" ); document.write( "Acid solution B 50 ----------------200-x liters
\n" ); document.write( "Total 20.00% ---------------- 200
\n" ); document.write( "..............
\n" ); document.write( "10x+50(200-x)=20*200
\n" ); document.write( "10x+10000-50x=4000
\n" ); document.write( "10x-50x =4000-10000
\n" ); document.write( "-40x=-6000
\n" ); document.write( "/-40
\n" ); document.write( "x=150 liters 10.00% \r
\n" ); document.write( "\n" ); document.write( "50 liters 50.00%
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