document.write( "Question 424905: trains A and B are travelling in the same direction on parellel tracks. train A is travelling at 60 miles per hour and train B is travellling at 80 miles per hour. Train A passes a station at 11:10 pm. If train B passes the same station at 11:25 pm, at what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #296056 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Train A 60 mph \n" ); document.write( "Train B 80 mph \n" ); document.write( " \n" ); document.write( "Train A passes station at 11:10 \n" ); document.write( "Train B passes station at 11:25 \n" ); document.write( " \n" ); document.write( "Difference in time= 00:15 15 \n" ); document.write( "Train Awill have covered 15 miles before Train B \n" ); document.write( " \n" ); document.write( "catch up distance= 15 miles \n" ); document.write( "catch up speed = 80 -60 mph \n" ); document.write( "catch up speed = 20 mph \n" ); document.write( " \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 15 / 20 \n" ); document.write( "catch up time= 0.75 hours \n" ); document.write( "catch up time= 45 minutes \n" ); document.write( "catch up at 12:10 AM \n" ); document.write( " \n" ); document.write( " |