document.write( "Question 424843: how many liters of a 10 percent alcohol solution must be mixed with 70 liters of the solution that is 80 percent alcohol to get a solution that is 20 percent alcohol \n" ); document.write( "
Algebra.Com's Answer #296043 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alcohol 80 ---------------- 70
\n" ); document.write( "Alcohol 10 ---------------- x
\n" ); document.write( "Total 20 ---------------- 70+x
\n" ); document.write( "....
\n" ); document.write( "80*70+10 *x=20(70 +x)
\n" ); document.write( "5600+10x =1400+20 x
\n" ); document.write( "10x-20x= 1400-5600
\n" ); document.write( "-10x=-4200
\n" ); document.write( "/-10
\n" ); document.write( "x=420 liters 10% Alcohol
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