document.write( "Question 424823: x2+7x+12=0 \n" ); document.write( "
Algebra.Com's Answer #296029 by linh117(31)\"\" \"About 
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x2+7x+12=0\r
\n" ); document.write( "\n" ); document.write( "x^(2)+7x+12=0\r
\n" ); document.write( "\n" ); document.write( "For a polynomial of the form x^(2)+bx+c, find two factors of c (12) that add up to b (7). In this problem 4*3=12 and 4+3=7, so insert 4 as the right hand term of one factor and 3 as the right-hand term of the other factor.
\n" ); document.write( "(x+4)(x+3)=0\r
\n" ); document.write( "\n" ); document.write( "Set each of the factors of the left-hand side of the equation equal to 0.
\n" ); document.write( "x+4=0_x+3=0\r
\n" ); document.write( "\n" ); document.write( "Since 4 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 4 from both sides.
\n" ); document.write( "x=-4_x+3=0\r
\n" ); document.write( "\n" ); document.write( "Set each of the factors of the left-hand side of the equation equal to 0.
\n" ); document.write( "x=-4_x+3=0\r
\n" ); document.write( "\n" ); document.write( "Since 3 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 3 from both sides.
\n" ); document.write( "x=-4_x=-3\r
\n" ); document.write( "\n" ); document.write( "The complete solution is the set of the individual solutions.
\n" ); document.write( "x=-4,-3 \n" ); document.write( "
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