document.write( "Question 424820: The perimeter of a rectangle is 66m. The length of the rectangle is 1m more than three the width. Find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #296028 by linh117(31) $\"\"$ $\"About$

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66 = 2(l+w)
\n" ); document.write( "l = 3w + 1
\n" ); document.write( "plug l in formula and solve\r
\n" ); document.write( "\n" ); document.write( "66= 2[(3w+1)+w]
\n" ); document.write( "66= 2(4w+1)
\n" ); document.write( "66= 8w +2
\n" ); document.write( "64=8w
\n" ); document.write( "w=8\r
\n" ); document.write( "\n" ); document.write( "l= 3(8) +1
\n" ); document.write( "l=24 +1
\n" ); document.write( "l=25
\n" ); document.write( " \n" ); document.write( "

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