document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424820>Question 424820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 66m.  The length of the rectangle is 1m more than three the width. Find the dimensions of the rectangle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296027 by </B><A HREF=/tutors/aboutme.mpl?userid=Adrish><B>Adrish(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adrish><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solutions:\r<BR>\n" );
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document.write( "Let the Width be \"x\"\r<BR>\n" );
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document.write( "Then the rectangle will be 1+3x\r<BR>\n" );
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document.write( "Given: Perimeter= 66m\r<BR>\n" );
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document.write( "We Know  P= 2L + 2W\r<BR>\n" );
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document.write( "66= 2( 1+3x) + 2x\r<BR>\n" );
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document.write( "66= 2+6x+2x<BR>\n" );
document.write( "66-2= 2-2 +8x<BR>\n" );
document.write( "64= 8x<BR>\n" );
document.write( "x=64/8\r<BR>\n" );
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document.write( "x=8m\r<BR>\n" );
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document.write( "Therefore the Length= 1+3(8)<BR>\n" );
document.write( "                    = 25m\r<BR>\n" );
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document.write( "Width= 8m </SPAN>\n" );
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