document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44743>Question 44743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My Question\r<BR>\n" );
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document.write( "A tin which is 12 cm long, 9 cm wide and 4 cm deep holds 120 g of tea. If 1 kg of the same tea is packed into a tin which has a 12 cm square base, how tall will the tin have to be ?\r<BR>\n" );
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document.write( "Please help me to solve this. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29602 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A tin which is 12 cm long, 9 cm wide and 4 cm deep holds 120 g of tea. If 1 kg of the same tea is packed into a tin which has a 12 cm square base, how tall will the tin have to be ?<BR>\n" );
document.write( "VOLUME OF TIN =L*B*H=12*9*4=432 CC<BR>\n" );
document.write( "IT HOLDS 120 GM.OF TEA<BR>\n" );
document.write( "TO HOLD 1 KG=1000 GMS..WE NEED <BR>\n" );
document.write( "1000*432/120 =36000 CC<BR>\n" );
document.write( "BASE AREA OF NEW TIN =A=12*12=144 SQ.CM.<BR>\n" );
document.write( "HENCE HT NEEDED =V/A=36000/144=250 CM<BR>\n" );
document.write( "Please help me to solve this. Thanks. </SPAN>\n" );
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