document.write( "Question 424764: Suppose you know the base of a rectangle has a length of 5 inches and a diagonal has a length of 13 inches. Find the area of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #296016 by linh117(31)\"\" \"About 
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solve like 2 triangles\r
\n" ); document.write( "\n" ); document.write( "A= 1/2 bh\r
\n" ); document.write( "\n" ); document.write( "Pythagorean theorem for third side\r
\n" ); document.write( "\n" ); document.write( "A^2 + B^2 = C^2\r
\n" ); document.write( "\n" ); document.write( "5^2 + B^2 = 13^2\r
\n" ); document.write( "\n" ); document.write( "25 + B^2 = 169\r
\n" ); document.write( "\n" ); document.write( "B^2 = 144\r
\n" ); document.write( "\n" ); document.write( "b= 12\r
\n" ); document.write( "\n" ); document.write( "A= 1/2(5)(12)
\n" ); document.write( "A=30
\n" ); document.write( "area of rectangle equal 30*2=60 inches^2
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