document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424756>Question 424756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An amateur drama group hire a theatre for their production. They expect to sell all 850 tickets, some at $12 and the rest at $8. The group require the ticket sales to cover their $3760 production costs and to make a profit of $4000. If they are to exactly achieve this target and their expectations regarding ticket sales are correct how many of the 850 tickets should they charge $12 for and how many should they charge $8 for?\r<BR>\n" );
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document.write( "(Need help thanks!!)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296001 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of $8 tickets.  <BR>\n" );
document.write( "Then 850-x = the number of $12 tickets.<BR>\n" );
document.write( "Setting up the problem in equation form, we have<BR>\n" );
document.write( "8x + 12(850-x) = 3760 + 4000<BR>\n" );
document.write( "Collect terms and solve for x:<BR>\n" );
document.write( "-4x + 10200 = 7760 -> x = 610<BR>\n" );
document.write( "So they need to sell 610 $8 tickets and 850 - 610 = 240 $12 tickets<BR>\n" );
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