document.write( "Question 44750: equation with 3 linear variables\r
\n" ); document.write( "\n" ); document.write( "2x-y+z=10
\n" ); document.write( "4x+2y-3z=10
\n" ); document.write( "x-3y+2z=8\r
\n" ); document.write( "\n" ); document.write( "wouldn't you divide the first equation by 2?
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Algebra.Com's Answer #29600 by venugopalramana(3286)\"\" \"About 
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\n" ); document.write( "YOU CAN DIVIDE EQN.I WITH 2 AND ADD TO EQN.III TO ELIMINATE X
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\n" ); document.write( "x - y + z = 2
\n" ); document.write( "-x + y + z = 4
\n" ); document.write( "-x + z = 2
\n" ); document.write( "augmented matrix is
\n" ); document.write( "1.....................-1.......................1.............................2
\n" ); document.write( "-1.....................1.......................1.............................4
\n" ); document.write( "-1.....................0.......................1.............................2
\n" ); document.write( "nr2=r2+r1 and nr3=r3+r1
\n" ); document.write( "1..................-1.................1.............2
\n" ); document.write( "1-1=0............1-1=0............1+1=2..........2+4=6
\n" ); document.write( "1-1=0...........-1+0=-1...........1+1=2..........2+2=4
\n" ); document.write( "nr2=r2/2....nr3=r3-r2
\n" ); document.write( "1....................-1...............1..............2
\n" ); document.write( "0/2=0.............0/2=0..............2/2=1........6/2=3
\n" ); document.write( "0-0=0............-1-0=-1..............2-2=0.......4-6=-2
\n" ); document.write( "nr1=r1-r3-r2.......nr2=2r2........nr3=-r3
\n" ); document.write( "1-0-0=1............-1+1-0=0.........1-0-1=0.......2+2-3=1
\n" ); document.write( "0.....................0...................1............3
\n" ); document.write( "0.....................1...................0.............2
\n" ); document.write( "exchange r2 and r3
\n" ); document.write( "1....0........0.......1
\n" ); document.write( "0....1........0.......2
\n" ); document.write( "0....0........1.......3
\n" ); document.write( "hence x=1......y=2.....z=3
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