document.write( "Question 424706: The sum of the digits of a three digit number is 17. The middle digit is two more than the first digit. The third digit is one less than twice the first digit. Find the number. \n" ); document.write( "
Algebra.Com's Answer #295986 by ankor@dixie-net.com(22740)\"\" \"About 
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let the 3 digits be x, y, z
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\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( "\"The sum of the digits of a three digit number is 17.\"
\n" ); document.write( "x + y + z = 17
\n" ); document.write( ":
\n" ); document.write( "\" The middle digit is two more than the first digit.\"
\n" ); document.write( "y = x+2
\n" ); document.write( ":
\n" ); document.write( "\"The third digit is one less than twice the first digit.\"
\n" ); document.write( "z = 2x - 1
\n" ); document.write( ":
\n" ); document.write( "Find the number.
\n" ); document.write( "using the 1st equation, substitute for y and z from the 2nd and 3rd equations
\n" ); document.write( "x + (x+2) + (2x-1) = 17
\n" ); document.write( "4x + 1 = 17
\n" ); document.write( "4x = 17 - 1
\n" ); document.write( "4x = 16
\n" ); document.write( "x = 4
\n" ); document.write( ":
\n" ); document.write( "I'll let you find y and z, make sure they add up to 17 \n" ); document.write( "
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