document.write( "Question 424691: a cyclist traveled to her destination at an average rate of 15 mph. By traveling 3 mph faster, she took 30 minutes less to return. what distance did she travel each way? \n" ); document.write( "
Algebra.Com's Answer #295969 by stanbon(75887)\"\" \"About 
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a cyclist traveled to her destination at an average rate of 15 mph. By traveling 3 mph faster, she took 30 minutes less to return. what distance did she travel each way?
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\n" ); document.write( "Slow speed DATA:
\n" ); document.write( "rate = 15 mph; distance = x miles ; time = d/r = x/15 hrs
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\n" ); document.write( "Faster speed DATA:
\n" ); document.write( "rate = 18 mph; distance = x miles ; time = x/18 hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "slow time - faster time = 1/2 hr
\n" ); document.write( "x/15 - x/18 = 1/2
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\n" ); document.write( "Multiply thru by 90 to get:
\n" ); document.write( "6x - 5x = 45
\n" ); document.write( "x = 45 miles (distance she traveled each way)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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