document.write( "Question 424691: a cyclist traveled to her destination at an average rate of 15 mph. By traveling 3 mph faster, she took 30 minutes less to return. what distance did she travel each way? \n" ); document.write( "
Algebra.Com's Answer #295969 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a cyclist traveled to her destination at an average rate of 15 mph. By traveling 3 mph faster, she took 30 minutes less to return. what distance did she travel each way? \n" ); document.write( "---- \n" ); document.write( "Slow speed DATA: \n" ); document.write( "rate = 15 mph; distance = x miles ; time = d/r = x/15 hrs \n" ); document.write( "---- \n" ); document.write( "Faster speed DATA: \n" ); document.write( "rate = 18 mph; distance = x miles ; time = x/18 hrs \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "slow time - faster time = 1/2 hr \n" ); document.write( "x/15 - x/18 = 1/2 \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 90 to get: \n" ); document.write( "6x - 5x = 45 \n" ); document.write( "x = 45 miles (distance she traveled each way) \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |