document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44745>Question 44745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir,<BR>\n" );
document.write( " MY friend had done this but I can't really understand what he had written.\r<BR>\n" );
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document.write( "The cross-section of a drain is a rectangle 30 cm wide. If the water 3.5 cm deep flows along the drain at a rate of 22 cm per second, how many litres of water will flow through each minute ?\r<BR>\n" );
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document.write( "Volume = width x depth x height \r<BR>\n" );
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document.write( "(width and depth are given namely 30 and 3.5 as for the height is the water flows along the drain is consider its length, in this case, 22 ? (Am I right ?)\r<BR>\n" );
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document.write( "If this is true, volume per second = 30 x 3.5 x 22 =  2310 cm^3<BR>\n" );
document.write( "Therefore, volume per minute = 2310 x 60 = 138600<BR>\n" );
document.write( "Since the answer is required in litres thus 138600 cm^3 = 138 600/1000 = 138.6 litre.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29593 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I didn't check your arithmetic but <BR>\n" );
document.write( "the logic looks right.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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