document.write( "Question 424440: please. could you explain in details for this college algebra problem?\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The population of a certain endangered species of owl is declining exponentially. There are currently 450 living specimens, whereas just 8 years ago there were 12,000 . If the population continues to decline exponentially, how long will it be until there is only a single owl left?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #295895 by Gersid(33)\"\" \"About 
You can put this solution on YOUR website!
This is a problem in exponential decay for which you can use the exponential function: \"y+=+ab%5Ex\", where the base, b, is between 0 and 1 for exponential decay. x is the number of years given in the problem (x = 8).
\n" ); document.write( "Start with the exponential function:
\n" ); document.write( "\"y+=+ab%5Ex\" Substitute y = 450, the current number of owls. a = 12,000, the number of owls 8 years ago, and x = 8.
\n" ); document.write( "\"450+=+%2812000%29b%5E8\" Solving for b will give you the exponential function for this situation.
\n" ); document.write( "\"b%5E8+=+450%2F12000\" Use your calculator to take the eighth root of both sides.
\n" ); document.write( "\"b+=+0.6634\" Approx. Now you can write the exponential function for this situation:
\n" ); document.write( "\"y+=+12000%280.6634%29%5Ex\"
\n" ); document.write( "The question you want to answer is - For what value of x (x = number of years) will y (the number of owls remaining) = 1.
\n" ); document.write( "\"1+=+12000%280.6634%29%5Ex\" Solve for x. Divide both sides by 12000.
\n" ); document.write( "\"1%2F12000+=+%280.6634%29%5Ex\" Take the logarithm of both sides.
\n" ); document.write( "\"Log%281%2F12000%29+=+xLog%280.6634%29\" From the power rule for logarithms.
\n" ); document.write( "\"x+=+Log%281%2F12000%29%2FLog%280.6634%29\" Use your calculator to evaluate.
\n" ); document.write( "\"x+=+22.8878\" years.
\n" ); document.write( "
\n" ); document.write( "
\n" );