document.write( "Question 424435: loga x + loga(x-2)=loga3 \n" ); document.write( "
Algebra.Com's Answer #295880 by Gogonati(855)\"\" \"About 
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Solve:logax+loga(x-2)=loga3\r
\n" ); document.write( "\n" ); document.write( " loga x(x-2)=loga 3\r
\n" ); document.write( "\n" ); document.write( " x(x-2)=3\r
\n" ); document.write( "\n" ); document.write( " \"x%5E2-2x-3=0\" is a quadratic equation, which can be written:\r
\n" ); document.write( "\n" ); document.write( " \"%28x%2B1%29%2A%28x-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "x+1=0 => x=-1 and x-3=0 => x=3 The roots are {-1, 3}\r
\n" ); document.write( "\n" ); document.write( "Since the logarithm of negative numbers doesn't exist the value x=-1 is rejected.\r
\n" ); document.write( "\n" ); document.write( " Answer.The solution set is {x: x=3}
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