document.write( "Question 424435: loga x + loga(x-2)=loga3 \n" ); document.write( "
Algebra.Com's Answer #295880 by Gogonati(855)![]() ![]() You can put this solution on YOUR website! Solve:logax+loga(x-2)=loga3\r \n" ); document.write( "\n" ); document.write( " loga x(x-2)=loga 3\r \n" ); document.write( "\n" ); document.write( " x(x-2)=3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+1=0 => x=-1 and x-3=0 => x=3 The roots are {-1, 3}\r \n" ); document.write( "\n" ); document.write( "Since the logarithm of negative numbers doesn't exist the value x=-1 is rejected.\r \n" ); document.write( "\n" ); document.write( " Answer.The solution set is {x: x=3} \n" ); document.write( " |