document.write( "Question 424393: a ball is thrown, its height in feet h after t seconds is given:
\n" ); document.write( "h=vt-16t^2
\n" ); document.write( "v=initial upward velocity in feet per second. if v=21 feet per second, find all values of t which h=6 feet. Do not round intermediate steps, round answer 2 decimals. THANK YOU!!!!!\r
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Algebra.Com's Answer #295869 by lwsshak3(11628)\"\" \"About 
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a ball is thrown, its height in feet h after t seconds is given:
\n" ); document.write( "h=vt-16t^2
\n" ); document.write( "v=initial upward velocity in feet per second. if v=21 feet per second, find all values of t which h=6 feet. Do not round intermediate steps, round answer 2 decimals.\r
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\n" ); document.write( "\n" ); document.write( "equation:
\n" ); document.write( "6=21t-16t^2
\n" ); document.write( "-16t^2+21t-6=0
\n" ); document.write( "16t^2-21t+6=0
\n" ); document.write( "solve by quadratic formula,
\n" ); document.write( "a=16, b=-21, c=6\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( "t=(-(-21)+-sqrt(21^2-4*16*6))/2*16
\n" ); document.write( " =(21+-sqrt(441-384))/32
\n" ); document.write( " =(21+-sqrt(57))/32
\n" ); document.write( " =(21+sqrt(57)/32 or (21-sqrt(57)/32
\n" ); document.write( " =0.89 sec or 0.42 sec
\n" ); document.write( "ans:
\n" ); document.write( "The ball reaches a height of 6 feet after 0.42 sec on its way up and returns to a height of 6 feet after 0.89 sec on its way down.
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