document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424363>Question 424363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man runs to a telephone and back in 15 minutes. His speed on the way to the telephone is 5m/s and his speed on the way back is 4m/s. Find the distance to the telephone.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295843 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man runs to a telephone and back in 15 minutes. His speed on the way to the telephone is 5m/s and his speed on the way back is 4m/s. Find the distance to the telephone.\r<BR>\n" );
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document.write( "\"To\" DATA:<BR>\n" );
document.write( "rate = 5 m/s ; d =  x meters ; time = x/5 minutes<BR>\n" );
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document.write( "\"Back\" DATA:<BR>\n" );
document.write( "rate = 4 m/s ; d =  x meters ; time = x/4 minutes<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "time + time = 15 minutes<BR>\n" );
document.write( "x/5 + x/4 = 15<BR>\n" );
document.write( "4x + 5x = 300<BR>\n" );
document.write( "9x = 300<BR>\n" );
document.write( "x = 33 1/3 meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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