document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44729>Question 44729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if F(x)=-3x+2, what are the values of m and b so that F(mx=b)=2x-3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29583 by </B><A HREF=/tutors/aboutme.mpl?userid=adamchapman><B>adamchapman(301)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adamchapman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F(x)=-3x+2<BR>\n" );
document.write( "Thuis means that to find F(x), you must multiply what is in the brackets on the left hand side (x) by -3, and then add 2.<BR>\n" );
document.write( "F(mx+b)=-3(mx+b)+2<BR>\n" );
document.write( "We know that this is equal to 2x-3, so:<BR>\n" );
document.write( "-3(mx+b)=2x-3<BR>\n" );
document.write( "-3mx-3b=2x-3<BR>\n" );
document.write( "Equating coefficients of x:<BR>\n" );
document.write( "-3m=2<BR>\n" );
document.write( "m=-2/3<BR>\n" );
document.write( "Equating constant terms:<BR>\n" );
document.write( "-3b=-3<BR>\n" );
document.write( "b=1<BR>\n" );
document.write( "so the solution is m=-2/3 and b=1<BR>\n" );
document.write( "F(-2x/3+1)=2x-3\r<BR>\n" );
document.write( "\n" );
document.write( "I hope this helps.<BR>\n" );
document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk<BR>\n" );
document.write( "Adam\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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