document.write( "Question 424302: the speed of train a is 6 mph slower than the speed of train b.Train A travels 200 miles in the same time it takes train b to travel 230 miles. What is the speed of each train? \n" ); document.write( "

Algebra.Com's Answer #295824 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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the speed of train a is 6 mph slower than the speed of train b.
\n" ); document.write( "Train A travels 200 miles in the same time it takes train b to travel 230 miles.
\n" ); document.write( "What is the speed of each train?
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of the slower train (a)
\n" ); document.write( "then
\n" ); document.write( "(s+6) = speed of the faster train (b)
\n" ); document.write( ":
\n" ); document.write( "Write time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Fast train time = slow train time
\n" ); document.write( " $\"230%2F%28%28s%2B6%29%29\"$ = $\"200%2Fs\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "230s = 200(s+6)
\n" ); document.write( "230s = 200s + 1200
\n" ); document.write( "230s - 200s = 1200
\n" ); document.write( "30s = 1200
\n" ); document.write( "s = $\"1200%2F30\"$
\n" ); document.write( "s = 40 mph is the speed of a, the slower train
\n" ); document.write( "then
\n" ); document.write( "40 + 6 = 46 mph is the speed of b
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "You can confirm this by finding the travel time of each train, should be equal \n" ); document.write( "

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